(2x)^2+(4x+20)^2=(6x)^2

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Solution for (2x)^2+(4x+20)^2=(6x)^2 equation: 



(2x)^2+(4x+20)^2=(6x)^2

We move all terms to the left:

(2x)^2+(4x+20)^2-((6x)^2)=0

determiningTheFunctionDomain
2x^2+(4x+20)^2-6x^2=0

We add all the numbers together, and all the variables

2x^2-6x^2+(4x+20)^2=0

We add all the numbers together, and all the variables

-4x^2+(4x+20)^2=0

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